Oligoribonucleotide X was treated with phosphatase (for removal of 3' and 5' - terminal phosphates), then with RNAase T1, which cleaves all phosphodiester bonds located in a 3' position of guanosine in a 5'-specific manner.
As a result, oligonucleotides L, M and N were generated in equal amounts. Each of them was further treated with phosphatase and subjected to alkaline hydrolysis. Results are listed in the table below.
Then experiment was modified: oligoribonucleotide X after treatment with phosphatase was hydrolyzed with RNAaseP, which cleaves all phosphodiester bonds in a 3'-position of pyrimidines in a 5' - specific manner.
This hydrolysis yielded five products in approximately equimolar concentrations: uridine monophosphate, cytidine monophosphate and oligonucleotides P, Q and R. After resolution of the mixture and alkaline hydrolysis of these oligonucleotides data listed in the table below were obtained.
My thinking : G can not be at the 5' end otherwise we would get a single Guanosine also in the first experiment. G can also not be at the second last from 3' end as we have not got any singles. We have got A and C in a duplet and so they must have been at the 3' end.
I also have trouble understanding the significance of "mole/mole of oligoribonucleotide".
I am trying to fit in other results but am unable to do so. A GOOD HINT WILL BE APPRECIATED MORE THAN A DIRECT ANSWER.