# Genotypic distribution of a population with two characteristics and linkage

I am currently doing some research into distributions and probabilities with Mendellian genetics. I came across this problem that I cannot seem to wrap my head around.

Given that the population has two characteristics, they are color and texture. Supposed two dihybrids reproduce (AaBb x AaBb) and if the dominant form of the color gene is contributed, then the dominant form of the texture gene is three times as likely to be contributed as the recessive form. If the recessive color gene is contributed then the dominant and recessive genes for texture are equally likely.

From this the geneotypic distribution has to be calculated.

I know the solution is:

[9/64   6/64   1/64   3/16   1/4   1/16   1/16   2/16   1/16]

AABB   AABb   AAbb   AaBB   AaBb  Aabb   aaBB   aaBb   aabb


When I performed the punnett square I got the distribution of:

 [1/16   2/16   1/16   2/16   4/16   2/16   1/16   2/16   1/16]

AABB   AABb   AAbb   AaBB   AaBb  Aabb   aaBB   aaBb   aabb


and did not know where to go from there.

My question is how did they incorporate the "times as likely" condition into the solution.

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What are these traits exactly ? just colors ? From the data it seems that homozygosity is not preferred – WYSIWYG Mar 5 '14 at 4:54