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Background

Talking about one particular phenotypic trait, the total phenotypic variance $V_p$ is decomposed into genetic and environmental variance for this trait, represented by the symbols $V_G$ and $V_E$ respectively. Also the covariance between genes and environment affect $V_p$ but we'll ignore it for the purpose of this question. The genetic variance $V_G$ can be further decomposed into dominance and additive variance. Similarly the environmental variance can be further decomposed into for example, for the mammals, the variance in the womb $V_W$ and the other environmental variance $V_{OE}$.

One could measure $V_W$ by looking at correlation between dizygotic twins.

Question

What part of the environmental variance in phenotype is explained by the variance in wombs' environments? In other words, How much is $V_W$ compared to $V_E$ and $V_P$?

Of course the answer will depends on the trait and on the species. But a general idea/estimation is very welcome. Is it around $\frac{V_W}{V_E} = 0.01$ or $\frac{V_W}{V_E} = 0.75$

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