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- Background -

Talking about one phenotypic trait, the total phenotypic variance $V_p$ is decomposed into genetic and environmental variance for this trait, represented by the symbols $V_G$ and $V_E$ respectively. Also the covariance between genes and environment affect $V_p$ but we'll ignore it for the purpose of this question.

$$V_p = V_E + V_G + O(Cov(E,G))$$

The genetic variance $V_G$ can be further decomposed into dominance and additive variance. Similarly the environmental variance can be further decomposed into for example, for the mammals, the variance in the womb $V_W$ and the other environmental variance $V_{OE}$.

$$V_p = V_w + V_{OE} + V_A + V_D$$

$$h_N^2 = \frac{V_A}{V_p} = \frac{V_A}{V_w + V_{OE}}$$

One could measure $V_W$ by looking at correlation between dizygotic twins.

- Question -

What part of the environmental variance in phenotype is explained by the variance in wombs' environments? i.e. what are the estimates of $\frac{V_w}{V_e}$ or what are the estimates of $\frac{V_w}{V_p} = \frac{V_w}{V_w + V_{OE}}$?

Of course the answer will depends on the trait and on the species. But a general idea/estimation is very welcome.

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