Take the 2-minute tour ×
Biology Stack Exchange is a question and answer site for biology researchers, academics, and students. It's 100% free, no registration required.

How do G-coupled protein receptors (GPCR) transmit signals through the plasma membrane?

Links containing information about this and pictures will be very helpful.

share|improve this question
add comment

1 Answer 1

up vote 5 down vote accepted

The G-coupled protein receptors (GPCR) transmit signals from outside of the cell into the cell and activate downstream signalling pathways. These change for example the expression of certain genes.

The whole process is a coorperation between the receptor, a G-protein, GTP as a co-factor and the ligand of the receptor (which starts the whole process). An extensive description (including much more images) is available in the Wikipedia, but in short, it looks like the images below (from the Wikipedia article on GPCR):

enter image description here

To answer how this signal is tranferred from the outside to the inside look at the first image: Upon ligand binding the conformation of the receptor changes its conformation and brings some of it transmembrane helices together so the G$\alpha$ subunit can bind here and activate downstream signalling.

enter image description here

The whole process happens in a few steps:

  1. In the resting state the receptor has a trimeric G-protein (consisting of the subunits $\alpha, \beta$ and $\gamma$ bound on its cytosolic site. The G-protein also has a GDP molecule bound to it $\alpha$ subunit.
  2. Upon binding of the ligand, the receptor changes its conformation, and G$\alpha$ exchanges the GD against GTP, which activates the complex.
  3. The G-protein dissociates into the active G$\alpha$ the G$\beta\gamma$ subunits, which signal to downstream signal transduction pathways like the MAP-Kinase pathway.
  4. Binding of RGS (regulator of G-protein signalling) to the g$\alpha$ subunit activates the intrinsic GTPase function of the subunit and hydrolyses GTP into GDP and P. The GDP stays bound to the G$\alpha$ subunit, which changes its conformation and forms the G-protein trimer at the receptor. At the receptor itself this induces also a change in conformation which makes the ligand dissociate from the receptor.

At the end of the fourth step the receptor has returned into its inactive form and stays there until the next ligand binding.

share|improve this answer
    
Thanks for your help.but intracellular signal transduction is well known property of gpcr i know the mechanism of that.i asked how gpcr transmit signal through plasma membrane –  N00B May 30 at 20:33
    
@N00B I added some information. But the whole process (especially the involvement of G-alpha) is connected and can not be seen seperated. –  Chris May 30 at 20:47
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.