Biology Stack Exchange is a question and answer site for biology researchers, academics, and students. It's 100% free, no registration required.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I am looking to find a highly competent E coli strain. I am making a library of a ~6.6kb plasmid and I am not getting high enough efficiency. Does anyone have a suggestion of a strain/protocol with ultrahigh efficiency (>1010).

share|improve this question
What strain did you decide on? Have you decided on an accepted answer? – user560 Nov 7 '12 at 1:16

I have heard that Epi300 electrocompetent cells (1) from Epicentre are very efficient: > 1 x 1010 cfu/µg of pUC19. Dan Gibson used them in his paper for the synthesis of the mitochondrial genome (2). We were also thinking of using them for our assemblies, but they are pretty expensive.

1. TransforMax™ EPI300™ Electrocompetent E. coli

2. Chemical synthesis of the mouse mitochondrial genome, Gibson et. al.

share|improve this answer
That's quite the downside to electrocompetent cells. They're very expensive (so are ultra high chemically competent cells). Then again, they're only recommend for libraries and assemblies, so next to all the screening, purification, genetic manipulation and sequencing you will be doing, this is a minor cost. – user560 Apr 20 '12 at 21:51
still this is the better answer - sometimes you have to pay a bit more if you are on the cutting edge. chemically competent cells are usually not as efficient. – shigeta Apr 21 '12 at 4:21
@shigeta - actually there are chemically competent cells that can achieve 1x10^10 cfu, and they're just as expensive as electrically competent cells. – user560 Apr 21 '12 at 14:06

This is a great question as I just made my own "homebrew" chemically competent cells.

There are a vast variety of E. coli strains that are commonly used for cloning. They may be transformed chemically by heat shock method, or electrically by electroporation (a brief summary may be found here). These can be made in the lab manually, or purchased commercially from reputable vendors (I recommend Invitrogen/Life Tech, NEB, Promega).

Chemically competency is achieved using Hanahan's method or some a variation thereof. The method involves washing the bacteria in a series of buffers containing various di-valent cation chloride salts (CaCl2, RbCl2, etc). Commercially available E. coli are sold as "regular" and "ultra" competent, ranging from 106 to 106 for regular, and the highest I've seen is 1010 cfu/µg DNA. For maximum efficiency, especially since a small plasmid such as yours will be easy to transform, electroporation is a more efficient technique, but requires specialized equpment. Electroporation can yield >1010 cfu/µg. For standard cloning practices, regular or high efficiency chemically competent E. coli are perfectly adequate. Since you mentioned you are creating a library, you certainly want to go with ultra high efficiency chemical transformation or, if you have the necessary equipment, electroporation. I have not seen electroporation efficiencies reported > 5x1010.

Transformation efficiencies are standardized by reporting a rate as the number of colony forming units (cfu) per µg of some control plasmid, typically pUC19. Transformation efficiency is very sensitive to many factors, including heat shock time, cooling times, thawing time, amount and size of plasmid DNA. All things being equal, the size and quantity of DNA are important for your purposes. Transformation efficiency generally increases with quantity of DNA, but there is a saturation point, and evenetually having too much DNA decreases the yield. Also, efficiency decreases linearly with plasmid size. For example, pUC19, the control vector, is ~2.7 kbp, and your library plasmid is ~6.6 kbp, so you should expect for the same mass of DNA you will have lost 60% transformation due to plasmid size. This loss is due to the physically larger size of DNA being more difficult to move into the bacteria.

share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.