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Calculating the frequency of a recessive allele in case of three segregating alleles

Is it correct to say: A. f(A) = p; f(a) = q B. p = f(AA) + ½ f(Aa)=$\sqrt{f(AA)}$? Also, For a gene locus segregating more than two alleles, the frequency of each allele is the frequency of ...
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Is this a simple Hardy-Weinberg problem?

Phenylketonuria is a severe developmental disability due to a rare autosomal recessive allele. Approximately 1 in every 10,000 newborns suffer from this disease. Calculate the frequency of the allele ...
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75 views

Disease causing variants and Hardy-Weinberg Equilibrium

Is it true that many disease causing variants/mutations do not follow Hardy Weinberg Equilibrium? If so, then please elaborate on why this may be true (or not) and provide examples. I am interested ...
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Evolution of a Population

Scientists observe a newly established population of sexually reproducing plants growing on the shore of a small island. An observable trait of the plant has two possible phenotypes. It is determined ...
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399 views

Hardy-Weinberg Equilibrium Question

I have four questions concerning H-W Equilibrium: (i) In a population of mice, the presence of black spots is the result of a homozygous recessive condition. If the frequency of the allele for this ...
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3answers
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Why is it $q^2$ for the individual count in hardy weinberg?

My understanding: In Hardy-Weinberg problems the frequency of a homozygous recessive genetic occurrence in a population is $q^2$. So if 1 in 100 people in a population have albinism (homozygous ...
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202 views

Recessive alleles at Hardy-Weinberg equilibrium

I've run into a question that I disagree with others on but I would like to receive the input of others. The question is: If a population is at Hardy-Weinberg equilibrium, which of the following can ...
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1answer
269 views

Hardy-Weinberg Color-blind

In a city, 4% of male population have color blindness. How many of the female are (a) color blind carrier, (b) color blind? Suppose the city holds Hardy Weinberg equilibrium. My progress: 4% of male ...
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510 views

Hardy Weinberg problem help!

The three common genotypes at the hemoglobin locus have very different phenotypes: SS individuals suffer from severe anemia, AS individuals have a relatively mild form of anemia but are resistant to ...
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2answers
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X Linked Hardy Weinberg Equilibrium Problem

In a given population under Hardy Weinberg equilibrium, 40.0% of men have hemophilia. What is the probability that a random man and random woman will have a daughter with haemophilia? I think the ...
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252 views

calculate the number of heterozygotes [closed]

The ability to taste PTC is due to a single dominant allele "T". You sampled 215 evolution students, and determined that 150 could detect the bitter taste of PTC and 65 could not. Assuming this trait ...
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181 views

Hardy Weinberg Equilibrium problem

In a small tribal population, the frequencies of two alleles A and a at a particular locus were 0.3 and 0.7, respectively. However, not all the individuals with genotype aa could live up to the ...
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Hardy Weinberg Equilibrium after 5 Generations

1 There is a population not at HWE where red eye = $a^+$ (dominant) and white eyes = $a^-$. If: $a^+/a^+ = 0.6$ $a^-/a^+ = 0.1$ $a^-/a^- = 0.3$ what are the frequencies of the $a^+$ and $a^-$ ...