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Unfortunately, that isn't a very well-written problem, but I think I can help. If we assume simple Mendelian genetics, this would be a monohybrid cross, as you're only examining one trait (flower color). You have a pure-breeding white flower and a pure-breeding red flower. These make up the P (parental) generation. Their offspring will be the F1 (first ...


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Assuming that red is homozygous dominant and white is homozygous recessive, this may help you: http://faculty.ucc.edu/biology-rohrer/Bio112_Files/mendel-punnett.pdf


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The way that your teacher describes is a way used by most of the introductory biology student. If you understand why that way is correct, it will seem more "concrete" to you. It is because there is less probability of having recombinants.


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In the beta-Lactamase test, an inhibitor of beta-Lactamase is added to a sample of the culture medium. The inhibitor binds to the enzyme and changes its color, which is in direct correlation to the concentration of the beta-Lactamase. More b-lactamase means more inhibitor binding and this results in more color development leading to a higher absorption. So ...


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This kind of thing is normally calculated using the $K_{a}/K_{s}$ ratio, the ratio of synonymous to non-synonymous substitutions. It is not enough to count mutations for coding sequences, you should also take into account whether or not that mutation will actually change the resulting product. There are various online tools that can help you do this, for ...


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I got .59. In response to WYSIWYG: (Note: I'm using A and a for the two alleles. My copy of Bulmer uses B for the second, which makes a little more sense if the alleles are codominant.) a.) The AA x aa cross should be twice as common as the AA x AA and aa x aa crosses, just as HT is more common than HH or TT when we toss a pair of identical coins. In ...


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It does make a difference on polyacrylamide. A and C are faster while G and T are slower. Image from publication: The "standards" are AAA/TTT/GGG/CCC molecules.


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Practically speaking I have never seen a difference, but the agarose gels usually used in the lab do not have the highest resolution. There is one paper showing that the form (A- or B- form) and the GC-content play a role since DNA molecules of higher GC content are less flexible and therefore have more problems getting through the agarose matrix. ...


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From the source that Amory cites : You know that the number of offspring is shown by Pascal's triangle, right? For two alleles you have 1 : 2 : 1 For three alleles 1 : 3 : 3 : 1 For four 1 : 4 : 6 : 4 : 1 etc. So, if 4 in 1000 are 12 and 36 cm tall, that means that every in 250 plants is tall like that. And on which level of ...


1

One of the alleles for each gene must come from the parent on the right hand side. That parent only has a and b alleles (is homozygous) - meiotic crossing over will not change this. So the offspring must inherit at least one a and one b. That should point you to the answer.


4

I think CT is an abbreviation for connective tissue. Some examples of its use in that fashion: http://en.wikipedia.org/wiki/Connective_tissue http://www.vetmed.vt.edu/education/curriculum/vm8054/Labs/Lab5/Lab5.htm http://www.pitt.edu/~sshostak/biosci1450/hislec03.html


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Question is: If an Ashkenazi(1/30) and(multiply) French-Canadian(1/30) .... Where 1/300 came from ? I duno, I may missing something - but may it be like that Parrent1(=1/30 * 1/2)*Parrent2(=1/30 * 1/2) = P(child with both mutations)


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Question a The only possible genotype that brings a phenotype of 12 inches is: $AABBCC$. Similarly the only possible genotype that bring a phenotype of 6 inches is: $aabbcc$. In consequence the offsprings can only be: $AaBbCc$ which measure $2+1+2+1+2+1 = 9$ inches. Question b Now the question is: if we breed two $AaBbCc$ how many offsprings measure 11 ...


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Lewis & Engelman (1983) Lipid bilayer thickness varies linearly with acyl chain length in fluid phosphatidylcholine vesicles. J. Mol. Biol. 166: 211 - 217. Table 1 and Figure 3 have the information that you need. For C14:0 the thickness of the hydrocarbon bilayer is given as 23 Å. Just in case this is homework, I'll leave you to convert that to ...



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