Standard protocol states having two compatible vectors being transformed simultaneously during the same procedure. I've come across a situation in which transforming one vector, obtaining results, and then transforming the other is preferable. Is there any reason to think that this wouldn't work? Do I risk losing my first vector upon transformation of the second?
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asked Apr 1, 2014 at 20:15
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2$\begingroup$ I'd assume that you use different antibiotic resistances for selection, that way you should be able to ensure that both plasmid are taken up successfully. $\endgroup$– Mad ScientistCommented Apr 1, 2014 at 20:21
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$\begingroup$ you do, but some will maintain both plasmids, so the two antiobitics on the plate still should give you want you want. $\endgroup$– shigetaCommented Apr 1, 2014 at 20:39
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1 Answer
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If the plasmids you wish to transform are very big (more than 20kb), the co-transformation might not be very efficient (you might not get any colonies). Electroporation should work though, as electrocompetent cells are more efficient than chemically competent cells. Alternatively, as you have read, you could transform your first plasmid and select for it, and then make these cell that harbor it competent and transform the second plasmid. As long as you select for the plasmids (with kan/carb/etc resistance marker), the cells that grow on the selective media will keep both of them. If I were you, I would try the co-transformation and then if it doesn't work I would do the sequential transformation.
answered Apr 1, 2014 at 20:56