As I understand, 2 ATP are consumed during steps 1 and 3 (glucose -> glucose-6-phosphate and fructose-6-phosphate -> fructose-1,6-bisphosphate) and then 4 ATP are produced during steps 6 and 9 (1,3-BPGA -> 3PGA and PEP -> pyruvate)
So that's 4 ATP produced - 2 ATP used = 2 ATP gained.
However, 2 NADH are produced during step 5 (3GPA -> 1,3 BPGA), and as we know 1 NADH gives 3 ATP so these 2 NADH should yield 6 ATP.
So, if we consider the ATP produced from the NADH, the net gain is 8 ATP. Is this correct?
cellular-respiration. I'm sure David has already written an answer elsewhere (citing Berg) that addresses this question. $\endgroup$
cellular-respiration, i've found 3 q&a that are kinda related to my question this does not talk about the NADH, this does not talk about the NADH in glycolysis specifically $\endgroup$