The solutions in the two arms of this U-tube are separated by a membrane that is permeable to water and glucose but not sucrose. Side A is half-filled with a solution of 2 M sucrose and 1 M glucose. Side b is half-filled with 1 M sucrose and 2 M glucose. Initially, the liquid levels on both sides are equal.
When it reaches equilibrium, the sugar concentrations on both sides of the U-tube will be 1.5 M sucrose and 1.5 M glucose.
Can somebody explain the answer (D) to me? My understanding is that the membrane is permeable to glucose, therefore glucose will reach equilibrium, with 1.5M on each side. Since the membrane is not permeable to sucrose, the concentration of sucrose will not change. Water will move from B to A. Does the movement of water causes the sucrose solution on both sides to be equal? But wouldn't that alter the glucose concentrations too? I'm sorry I just know what my bio teacher told me but I don't quite get the reasoning. Thanks.