The following table is from Deonier's text Computational Gene Analysis at p. 152. This is an exercise in global sequence alignment and scoring of alternative sequences. The text proposed a solution (in parentheses). Setting aside the upper left hand portion of the table it seems there may be a better path.
It's more likely I misunderstand the idea than that there is a typo.
$$\begin{array}{c | c | c | c | c | c | c |}- & -& T & G & G & T & G\\ \hline - & (0 ) & -2 & -4 & -6 &-8 & -10 \\ \hline A &(-2) & -1 & -3 & -5 & -7 & -9 \\ \hline T &-4 & (-1) & -2 & -4 & -4 & -6 \\ \hline C &-6 & -3 & (-2) & -3 & -5 & -5 \\ \hline G &-8 & -5 & -2 & (-1) & -3 & -4 \\ \hline T &-10 & -7 & -4 &-3 & (0) & (-2 )\\ \hline \end{array}$$
Just looking at the upper left corner,
$$\begin{array}{c | c | c |} (0) & -2 & -4...\\ \hline -2 & (-1) & -3...\\ \hline -4 & (-1) & -2...\\ \hline -6 & -3 & (-2)...\\ \hline \end{array}$$
which seems to give -7 versus -8 for the book's path. Below are the book's alignment and the one corresponding to my scoring, which may reveal my error.
$$\begin{array}{c | c | c | c | c | c | c |} A: & A & T & C & G & T & - \\ \hline B: & - & T & G & G & T & G \\ \hline \end{array}$$
$$\begin{array}{c | c | c | c | c | c | c |} A: & A & T & C & G & T & - \\ \hline B: & T & - & G & G & T & G \\ \hline \end{array}$$
I had no trouble constructing the matrix just scoring it. it's a small point but I don't like to move on without understanding it. Thanks for any assistance.
Edit: Both current answer seem clear on this but just for completeness: a match = 1; mismatch = -1; indel = -2.