1
$\begingroup$

I have calculated the probability that any child will have a particular blood type from both the genotype level and the phenotype level assuming the human ABO Rh system is followed.

Here are the genotype probabilities:

AA+/+ 49/1764
AA+/- 98/1764
AA-/- 49/1764
AO+/+ 98/1764
AO+/- 196/1764
AO-/- 98/1764
BB+/+ 49/1764
BB+/- 98/1764
BB-/- 49/1764
BO+/+ 98/1764
BO+/- 196/1764
BO-/- 98/1764
AB+/+ 98/1764
AB+/- 196/1764
AB-/- 98/1764
OO+/+ 49/1764
OO+/- 98/1764
OO-/- 49/1764

Here are the phenotype probabilities:

A+ 441/1764
A- 147/1764
B+ 441/1764
B- 147/1764
AB+ 294/1764
AB- 98/1764
O+ 147/1764
O- 49/1764

Here is the frequency of the blood types in the 1st generation by genotype:

AA+/+ 5/101
AA+/- 5/101
AA-/- 5/101
BB+/+ 5/101
BB+/- 5/101
BB-/- 5/101
AB+/+ 5/101
AB+/- 10/101
AB-/- 5/101
OO+/+ 5/101
OO+/- 5/101
OO-/- 5/101
AO+/- 10/101
AO+/+ 5/101
AO-/- 5/101
BO+/+ 4/101
BO+/- 4/101
BO-/- 4/101

Here are the numbers and their genders; a number represents an individual from a population of 101:

Male: 
0,2,5,10,11,17,20,22,23,31,34,40,41,44,46,47,50,55,59,61,62,68,71,79,80,82,85,88,89,92,94,100

Hermaphroditic(and fertile):
4,8,16,25,32,64 

all the rest are female

M/F mating: 11,904 offspring in 2nd generation H/A mating(hermaphrodites can mate with other hermaphrodites, males, females, and even themselves): 3636 offspring in 2nd generation

If you divide these by 6 you will get the amount per operation. The operations I am taking into consideration are +, -, *, /, ^, nth root, and arrow arrow(tetration).

So how can I take the frequency of blood types at the genotype level, probability of blood type at genotype and phenotype levels, and total number of offspring to get a 1st order estimate of the frequency of these blood types in the 2nd generation?

$\endgroup$
  • 3
    $\begingroup$ This question is very hard to read, I suggest that if you put some effort in to the formatting you'll more likely get a good answer :) $\endgroup$ – rg255 Dec 21 '14 at 19:50
  • $\begingroup$ "Here are the numbers and their genders:" ... what do you mean here? $\endgroup$ – rg255 Dec 22 '14 at 14:14
  • $\begingroup$ Since this biological data is from my Math World story numbers such as 0 and 100 have genders. Their gender is determined by 4 sex chromosomes. XXXX = female, XXXY = male, XXYY = hermaphroditic, and XYYY = male $\endgroup$ – Caters Dec 22 '14 at 19:47
  • $\begingroup$ So you mean there is 32(?) males, 6 hermaphrodites, and 101-(32+6) females?? $\endgroup$ – rg255 Dec 22 '14 at 20:38
  • $\begingroup$ yes that is what I mean $\endgroup$ – Caters Dec 22 '14 at 20:39

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.