We got this task:
There are 3 genes (acb) on one chromosome (linked inheritance). Distance a-c = 12cM, a-b=16cM. Probability for double crossing-over (CO) is 0,6%. Find ratio of genotypes of descendants (AcB/acb X acb/acb).
I don't know whether the 0,6% for double CO is included in the 16% (16cM) probability.
I think it is not, so I got these ratios: No CO and double CO: 42% AcB/acb, 42% acb/acb, 1x CO: 8% Acb/acb, 8% acB/acb