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Two heterozygote mice for skin color are reproduced. Black is dominant to white color. Find the probability that in 3 children 2 will be dark and one white. How did you do the ordering. Well I found it that in F1: 1/4 are AA, 1/2 Aa, 1/4 aa or 3/4 black and 1/4 white.Now nI think I should multiply the chances: 3/4*1/4*3/4, but it would be according to an order. What should I do? Is my answer correct?

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You are on the right track, but you have to keep in mind there are multiple ways to have two dark and one child in a group of three. You have to add the probabilities of each unique outcome that results in two dark and one light child. So, the probability is (1/4) x (3/4) x (3/4) PLUS (3/4) x (1/4) x (3/4) PLUS (3/4) x (3/4) x (1/4)

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  • $\begingroup$ Alternatively, multiply one outcome by 3P1. $\endgroup$ – March Ho Mar 1 '15 at 15:07

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