A high school class has analyzed plasmids by the help of restriction enzymes and electrophoresis.
The class got delivered two different plasmids, pBR 322 and pC 508. These two plasmids were going to be clipped by EcoR I and Hind III.
Figure 1 shows the two plasmids with specification of the two cutting points for EcoR I and Hind III.
Furthermore, the cutting points are also shown for the enzyme Pst I.
1) Analyze and explain the results in figure 2
2) What DNA-pieces would be formed if you had clipped with Pst I ?
1) You can see that the figure is showing the result of the restriction-analyzis. As for the plasmid pBR 322, you see that the result of the cutting of Hind III and EcoR I, is that both enzymes have the same size. Figure one shows that Hind III cuts over 0 bases and EcoR I cuts at 0 bases.
In pC508 you see that both enzymes have cut two times. EcoR I have cut at 1200 and 5800 bases, which you can see on figure 1. You can see the result of this in figure 2 (the gel electrophoresis). Hind III cuts at 6400 and 1200 bases, which again is an explanation as why the DNA-molecyles (figure 2) have different size.
2) If Pst I was used instead on the plasmid pBR 322, you would get the same size as Eco and Hind, because they all cut one place. If you had cut in pC508 you would get the bases 4800 and 6700 (as figure 1 shows)
Are these questions correctly answered?