The question is:
The frequency of a recessive allele a is 0.6. If a population is in Hardy-Weinberg equilibrium, what is the frequency of the dominant phenotype?
This question is a bit confusing to me. I'm not sure how to use my knowledge about Hardy-Weinberg in this problem. I know that when q = 0.6, p = 1 - 0.6 = 0.4. But when they are asking for the dominant phenotype, should it be p^2 or the squareroot of p? I have watched several YT-videos about this, but I still can't get the hang of it. There's not much help in my teacher or books. I would be really grateful if someone could clear up my confusions!