I have been given this question:
In a population of 2500 mice, light-colored fur is dominant to dark-colored fur. 2400 mice originally have light-colored fur. However, an owl species moves into their environment, preying mainly upon the light-colored mice as they are easier to spot when hunting at night. When the owls finally leave, 80% of the dark-colored mice are left, and only 10% of the light-colored mice. After many generations, Hardy-Weinberg equilibrium is re-established. Approximately what percentage of mice now have dark-colored fur?
Answer choices are:
My thought process goes as such:
When the owls leave, the groups are 240 light mice and 80 dark mice.
$q^2 + 2pq + p^2 = 1$
q is recessive allele, p is dominant allele.
$0.5^2 + 2*0.5*0.5 + 0.5^2 = 1$
$0.8*(0.5^2) + 0.1*(2*0.5*0.5) + 0.1*(0.5^2) = 0.275$
(0.8 and 0.1 correlate to the fitness of dark and light mice, respectively)
Now divide everything by 0.275 to figure out new allele frequencies:
$0.727 + 0.182 + 0.091 = 1$
This means that 0.727 = 73% is the new frequency for homozygous recessive (dark) mice.
However, the correct answer is B) 15%
Any idea what I did wrong/how the correct answer is achieved?