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While studying about membrane potential I usually come across the Na K pump . But I can't understand does it cause any generation of net charge in the cell If yes then how do charged cells stay together with other similarly charged ones , if not why and how not .

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It isn't neurons that are charged, it is their membranes. From the distance of other cells, they "see" both the charges inside and outside the membrane, so there isn't any substantial repulsion on that scale.

The charge across a membrane comes mostly not from the Na+/K+ pump directly, but due to differential permeability of the membrane to different ions. Ions normally tend to flow down their concentration gradients, but that flow can be influenced by an electrical potential. From the perspective of just Na+ and K+, there is more K+ inside the cell and more Na+ outside, and more permeability of the membrane to K+ than Na+. Therefore, the inside of the cell will be negatively charged at equilibrium where the net flow of ion charges is equal. At a negative resting potential, the negativity of the inside of the cell equalizes the net flow of potassium out with the net flow of sodium in. However, the actual concentration changes involved are miniscule. From the perspective of ion counts, there are basically as many positive ions inside as there are negative ions inside a cell; it's the very minute imbalance (fractions of a %) that gives a potential of ~-70mV.

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  • $\begingroup$ Look via the Na K pump we are pumping out net positive charge however miniscule it be how does it get balanced Or does it get balanced at all. $\endgroup$ Sep 24, 2017 at 4:45
  • $\begingroup$ The imbalance of charges from the Na/K pump doesn't actually matter much because ions can flow across the membrane through channels. You should just think about the Na/K pump as establishing a concentration gradient and ignore the 2 versus 3 ion imbalance. It just doesn't matter. The channels are a lot more important. The Na/K pump by itself can provide a couple mV but not the ~60-80mV that is typical. $\endgroup$
    – Bryan Krause
    Sep 24, 2017 at 6:48
  • $\begingroup$ But i still can't gauge whether cell turns out to be neutral or not $\endgroup$ Sep 24, 2017 at 7:44

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