I have a question from a past exam that asks the following:
"For the organism of genotype AABbCcDDEe (homozygous for 2 genes, heterozygous for 3 genes), how many different types of gametes will be made if the C gene and the E gene are linked on the same chromosome while the remaining genes are all on different chromosomes?"
However, I have no answer key, and these answers are the choices:
Here's my approach to the question:
We have 5 traits, and each trait consists of 2 alleles. To make functional gametes, each gamete must receive one of each allele so that it can survive. Clearly, for AA and DD, there's only one choice: A, and D.
However, for Bb, Cc, and Ee, things are a little different.
C and E are linked on the same chromosome. c and e are on different chromosomes. Therefore, a gamete can have either CE, or c and e. Similarly, a gamete can have either B or b.
Therefore, shouldn't we be able to create 4 different types of gametes?:
ABCDE, ABcDe, AbCDE, AbcDe
So wouldn't the answer be C. 4?
Please show me any mistakes I might be making, or any gaps in my understanding. This would be very much appreciated.