2
$\begingroup$

I am a student of Physiology, and I have ended up a bit confused after what I've read today regarding events during a threshold potential. So, while cells are in their resting membrane potential, the inward current of sodium is equal and opposite to the outward current of potassium. The same is true about the threshold potential.

When the threshold potential is reached, the inward sodium current is exactly equal and opposite to the outward potassium current. If this is true, why is there a change in the voltage of the membrane, let's say from -70 mV to -55 mV? I mean, both of the currents are equal and opposite and therefore there shouldn't be any change in the resting potential of the membrane.

$\endgroup$
2
  • $\begingroup$ Welcome Lydia. Obviously, of course threshold is different from resting potential, as the former generates an action potential and the latter does not. This question is really basic. What are your own thoughts about this? $\endgroup$
    – AliceD
    Commented Mar 17, 2018 at 22:38
  • $\begingroup$ Okay, so I know that in order for depolarization to occur, the influx of sodium must be greater than the efflux of potassium, and therefore the threshold potential is reached. However, I still don't understand how can the inward Na+ current be the same as outward K+ current in a threshold potential. I am sorry if the question is too basic, I just started the course few days ago. $\endgroup$ Commented Mar 17, 2018 at 22:46

1 Answer 1

1
$\begingroup$

Below is a figure showing the sequence of events during an action potential (AP). While the resting potential is characterized by an equilibrium, during an AP this balance is markedly 'disturbed'. The action potential is characterized by a specific timed series of events, namely the opening of Na+ channels in the initial depolarization phase, followed by an opening of K+ channels in the subsequent repolarization phase. During these phases, the Na+ and K+ currents are anything, but balanced.

AP
Fig. 1. Series of events during an AP. source: Brigham Young University-Idaho

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .