1
$\begingroup$

I am trying to understand how the inhibition constant is calculated for competitive inhibition.

$\frac{K^{app}}{V^{app}} = \frac{1+I/K_i}{V/K_m}$.

But often in secondary plots, $\frac{K^{app}}{V^{app}} $ vs Inhibitor concentration is plotted and the inhibition constant , $K_i$ is obtained from slope $1/K_i$. How is the slope equal to $1/K_i$ from the above equation? Could someone explain?

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.