1
$\begingroup$

16% of people in a population can not roll their tongue .what is the frequency of people which are heterozygous of this character? Please ,any one help and guide me to solve these kind of problems. I tried to solve it using punnet square but i failed . enter image description here

So i tried my best please help me to solve this.

$\endgroup$
  • $\begingroup$ Homework questions are off-topic on Biology unless you have shown your attempt at an answer. For more information see our homework policy. $\endgroup$ – David May 26 '18 at 8:50
  • $\begingroup$ @David He show some attempt. $\endgroup$ – L.Diago May 26 '18 at 9:19
  • $\begingroup$ Possible duplicate of Solving Hardy Weinberg problems $\endgroup$ – Remi.b May 26 '18 at 16:09
  • $\begingroup$ Hint: The very first step is to define which genotype can not roll their tongue. Then, you know that 16% of the population have these genotypes. From this, you can find out the frequency of heterozygote in the population thanks to Hardy-Weinberg. For more information, please look at the post marked as duplicate. $\endgroup$ – Remi.b May 26 '18 at 16:12
1
$\begingroup$

I deffinitly recomment to look at your calculations. But the abbility of cannot rolling tongue is recessive not dominant. And after all look at the Hardy-Weinberg equision p^2 + 2pq + q^2 = 1 (p*p=p^2). Try to extract the root of q^2 and you will get right sollution (because the 0.16 is squareroot).

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.