# Michaelis-Menten equation; how to find the constants from enzyme activity experimental results?

I was wondering what the constants in the Michaelis-Menten equation actually mean in experimental data of enzymes. How do I process the data to find Km and Kcat?

I did an experiment on catalase and its breakdown of hydrogen peroxide. I used a gas pressure sensor to track how much O2 was produced from the reaction over time. The following is an example raw plot of what I found. Point 0 is when I put the substrate and the reaction started (so I think I can call this the "maximum amount of substrate concentration" - in the Michaelis-Menten plot, it should be on the far right side.) To find the speed of the reaction at each point, I thought of finding the slopes between each point, which basically equates to finding the derivative. Since the raw plot I found looks like a logarithm function, so I would predict that the derivative would look like a hyperbola (with x > 0). Indeed, this is the (crude) graph of the "derivative" of the previous plot, which looks like a hyperbola: I believe that Kmax is the y-value of the first point in this graph - the initial velocity when the substrate is mixed with the enzyme. The substrate concentration is at highest at time 0, and the substrate concentration decreases as time increases.

So I thought, to make the Michaelis-Menten graph, I should flip the x-axis so that the substrate concentration is increasing along the x-axis. Yet, my problem was that if I do this, then the graph ends up not looking like the Michaelis curve... What I would have wanted to find is the Michaelis-Menten curve, so that I can also derive the Km and Kcat values. Does anyone know how to do this? Or am I doing my steps wrong? Thank you very much for helping me!

Michaelis-Menten Curve: • @lia the point is that you need to run this experiment multiple times, with multiple different starting concentrations of $H_2O_2$, find the initial (linear) rate for each, and then plot the rate vs. starting concentration. That's what this answer is trying to tell you. – De Novo Aug 22 '18 at 17:04