3' A T A G T A C C G C A T G T A C G G G C G A G A C A T T C G A G C A T T C A T 5'
This a Template DNA.
How to find the number of amino acids amino acids in the protein encoded by the above gene?
The answer is $7$.
My Try:
First I converted the above DNA to RNA and got
5' U A U C A U G G C G U A C A U G C C C G C U C U G U A A G C U C G U A A G U A 3'
Then I found the start codon which is A U G
5' U A U C |A U G| G C G U A C A U G C C C G C U C U G U A A G C U C G U A A G U A 3'
From here I am not understanding how to proceed.
Can anyone please explain how to solve this?