Anaerobic bacteria utilise glycolysis:

Glucose + 2 P + 2 NAD+ => 2 ATP + 2 H + 2 NADH + 2 H2O + 2 Pyruvate

followed by fermentation:

Pyruvate + NADH => Lactate + NAD+

The resultant NAD+ formed can then be used again to break down more glucose molecules in glycolysis to produce ATP.

However, besides NAD+, glycolysis also requires an input of 2 ATP at the beginning (for the phosphorylation of glucose to glucose 6P, and fructose 6P to fructose 1,6 BP)

Since only 2 ATP is produced from glycolysis initially, would these 2 ATP be reused in another round of glycolysis?

If so, how does anaerobic bacteria produce a net amount of ATP for cell activities and growth?

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    $\begingroup$ Please go back and check your sums and re-read the chapter in your text book, taking particular account of the fact that two molecules of triose are produced from one hexose. $\endgroup$ – David Sep 9 '18 at 9:23
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    $\begingroup$ That was already accounted for in the balanced equation above. 4 ATP - 2 ATP invested is a net of 2 ATP from glycolysis. $\endgroup$ – user60513 Sep 9 '18 at 10:32
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    $\begingroup$ What do you mean by "reused"? The net gain of the fermentative type of anaerobic energy extraction from glucose is 2ATP---which is available for cellular processes that need ATP to proceed. Note, that there are two ways to regenerate NAD+: fermentation (which you mention) and anaerobic respiration (which you do not mention); the net gain of anaerobic energy extraction from glucose involving anaerobic respiration is 2ATP & 2NADH, because the latter can be used to generate ATP (via ATP synthase). $\endgroup$ – user37894 Sep 9 '18 at 21:29
  • $\begingroup$ Your response to my comment is incorrect. As I said, please go back to your text book and look at the pathway of glycolysis and the actual reactions where ATP is generated and whether the substrate is triose or hexose and if it is triose how many trioses came from the original hexose. $\endgroup$ – David Sep 10 '18 at 21:43
  • $\begingroup$ @David the equation given by the OP is absolutely correct. Furthermore, the 2ATP 'obtained' may of course be used in another round of glycolysis (if that is what cell 'chooses' to do), leading to a net 'synthesis' of a further 2 ATP molecules: that is, for an initial 'investment' of two ATP you get 4 in return. The OP recognizes this. $\endgroup$ – user1136 Oct 9 '18 at 21:46

During the reactions, the resultant molecules are dispersed in the cytosol, and it is a bulk phenomenon rather discrete and independent event. The calculations are mainly based on in vitro experiments, so the reuse of the energy transporter molecules (ATP), totally depend on it's quick availability.

The NET production of ATP cannot be determined in precised manner as pathways may show reuse of the formed energy bags (ATPs) or may use already present molecule or molecules from some other reaction.


Some of the information contained in this post requires additional references. Please edit to add citations to reliable sources that support the assertions made here. Unsourced material may be disputed or deleted.

  • $\begingroup$ @VishalKumarSahu Can you please provide some references to support your answer? $\endgroup$ – WYSIWYG May 8 at 13:36

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