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As I'm teaching General Biology to my college students, I realized that I don't fully understand how a 3-P nucleotide like ATP is broken down to be incorporated into DNA during replication. How does this work??

In other words, what is the actual mechanism/reaction pathway for the following:

enter image description here

What I know:

I understand that ATP is typically hydrolyzed to become dephosphorylated in other contexts. I also understand that a phosphate of one nucleotide is bonded to a deoxyribose of an adjacent nucleotide via dehydration synthesis from the joining of their hydroxyl groups to form DNA.

However, I cannot seem to find a good resource (online or in any of my [admittedly simple] general bio textbooks) that demonstrate how exactly both of these reactions take place during replication...

I'm assuming that DNA polymerase is taking advantage of the released phosphates from ATP (and the appropriate forms of GTP, CTP, TTP) to become activated?

Overall, what does this whole process look like on a chemical/molecular level?

I'd love a visual (especially a video) if you could provide such a resource in addition to a thorough explanation of what's going on here.

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  • $\begingroup$ Molecular Biology of the Gene is a good book if you have access to it. $\endgroup$ – canadianer Oct 19 '18 at 15:38
  • $\begingroup$ I am unclear what you want to know. Is your question about the enzyme reaction mechanism or the thermodynamics? Your use of the word "power" in the title suggests energetically but the body of your question seems concerned with mechanistics. This and other statements about DNA polymerase "taking advantage of…" seem to indicate a basic ignorance of enzyme catalysis. Have you read the appropriate chapter in Berg et al ? $\endgroup$ – David Oct 20 '18 at 21:31
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    $\begingroup$ @David I want to know both and all of the above. $\endgroup$ – theforestecologist Oct 21 '18 at 1:28
  • $\begingroup$ If you want to know all then your thirst for knowledge admirable, but your question too wide to answer on SE Biology. I would read the appropriate chapters in Berg or Lodish etc. As regards your college students, what you focus on depends on their background and the time you have. The chemical aspects require a chemical background but don’t seem particularly interesting to me, except that the dNTP substrates drive the reaction energetically and pyrophosphatase makes it irreversible. Conceptual problems — proofreading, initiation and Okazaki fragments etc. — may be better. $\endgroup$ – David Oct 21 '18 at 17:49
  • $\begingroup$ @David. Thanks for the suggestions. I don't actually plan to teach them the specifics I'm asking about in this post -- these details are just for me to more fully understand the process as I explain to them a simplified version. Could you also more specifically indicate which texts you refer to? Is there a specific edition of Berg's or Lodish's texts? $\endgroup$ – theforestecologist Oct 21 '18 at 22:32
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I found this paper, which goes very deep into the molecular details of the individual steps of this reaction and also discusses how this is coupled to nucleotide selectivity.

The 'basic' details about the reaction (quoted from this section, which also has a nice figure):

The polymerization reaction proceeds by a simple nucleophilic attack of the 3'OH of the primer on the α-phosphate of the incoming dNTP followed by the elimination of pyrophosphate [...] The reaction uses a "two metal ion" mechanism in which metal ion A activates the 3'OH as a metal hydroxide while both metals A and B stabilizes the developing negative charge on the α-phosphate in the transition state.

The metal ions are Magnesium (Mg$^{2+}$) and are properly positioned by the enzyme structure and some additional amino acid side chains also help with the activation of the reaction.

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Apologia

The answer given by @Nicolai is essentially correct (and I have upvoted it). However I feel that the question embodies certain mistaken assumptions that should be challenged so that naïve readers of the question are not misled in to accepting them. (I refer to these below as ‘problems’.) I also feel that illustrations — not included in the answer provided by @Nicolai — are needed in this respect.)

Supporting authority

I have used a 2016 paper in Science by Gao and Wang as my authority, quoting from it and reproducing part of one of its figures for those who have not library access to this journal. The authors actually propound a ‘three-metal ion’ mechanism, rather than the ‘two-metal ion’ mechanism mentioned by @Nicolai. This, however does not affect the basic points I am making, although it serves to illustrate that the details of the enzyme mechanism are of a complexity that is unsuitable for teaching at an introductory level.

Here are two key frames from Fig. 1 of that paper:

Thermodynamics and Mechanism of phosophodiester bond formation

Problem 1

“I'm assuming that DNA polymerase is taking advantage of the released phosphates from ATP (and the appropriate forms of GTP, CTP, TTP) to become activated?”

An enzyme is not ‘activated’ by the products of the reaction it catalyses. The binding of the substrate may result in a conformation change that results in more favourable state for catalysis — and which might be referred to as ‘activation’‡ in a discussion of that topic; but the use of that word can only confuse at the level at which the current question is asked. This is because one of the key concepts in enzyme catalysis is ‘activation energy’ — the energy required to achieve the transition state. Activation energy refers to the activation of the reactants — not the enzyme. To quote from the paper:

Enzymes increase the rate of chemical reactions, which is thought to occur by a reduction in the activation energy required to reach the transition state (Fig. 1A)

Chemical reactions which result in a decrease in (Gibbs) Free Energy (the ‘Energy’ axis in Fig. 1A) are thermodynamically favourable. They occur slowly because they proceed through a transition state of higher energy. The role of an enzyme catalyst is to lower the energy to get to that transition state (the activation energy). As the figure shows, this reaction is thermodynamically favourable. The released pyrophosphate has no function, except to be hydrolysed by pyrophosphatases to prevent the polymerization being reversed.

Problem 2

It is unclear what the arrow at the left of the figure in the question (from the α-phosphate of the dNTP to the primer OH) is meant to represent†. Normally one would assume that this would be an electron, however here this does not make sense. As @Nicolai says

“…reaction proceeds by a simple nucleophilic attack of the 3'OH of the primer on the α-phosphate of the incoming dNTP”

i.e. the arrow should be from the oxygen electrons of the OH to the nucleophilic phosphate. This is shown in Fig. 1B (where the nascent DNA chain is on the left and the dNTP on the right). The latter figure actually shows the transition state, which allows one to see in a general way how this could be of lower energy than for the uncatalysed non-enzymic reaction. It is stabilized by the two metal ions (Mg2+), which themselves are held in the appropriate position by acidic side-chains at the active site of the enzyme.

Footnotes
‡As @user1136 points out, the expression ‘enzyme activation’ is also used to describe action of positive allosteric effectors — small molecules that increase the activity of the active site by a structural change initiated by their binding at a site distal from the active site — the allosteric site. This is a further potential cause of confusion as it has no relevance here.

†In a comment, the poster writes “The arrow in the… picture… represents conceptual movement of molecules and not ‘real-world’ chemical interactions”. If this is what was intended (I am not familiar with the source), in my opinion the authors should have used a different style of arrow (e.g. a wider one, ➡︎ rather than ➛, and not drawn it from the phosphate to the OH. It betrays a lack of either knowledge or concern for chemical conventions, and is particularly misleading for the student who wishes to understand biology at a chemical level. I find it inexcusable in a publisher with a reputation like that of Benjamin.

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  • $\begingroup$ My plan is actually not to teach at as advanced level as you describe. My hope is (as a forest ecologist) to better understand the true molecular/biochemical workings of this process so that I -- being then more properly informed -- could simplify the material in such a way that I wasn't actually perpetuating/teaching pseudo-truths. Thanks for providing some clarifications. $\endgroup$ – theforestecologist Dec 1 '18 at 23:29
  • $\begingroup$ @theforestecologist OK. I'll remove my last para. $\endgroup$ – David Dec 1 '18 at 23:32
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    $\begingroup$ The image that you mention under "Error 2" is from Starr et al.'s (2013) textbook "Biology: The Unity & Diversity of Life." Being an introductory biology textbook, the image is not trying to depict movement of atoms or subatomic particles. Rather, the arrow you've criticized is simply meant to be conceptual: it shows that the incoming tri-phosphate nucleotide bonds to the 3' hydroxyl group of the existing nucleic acid backbone. $\endgroup$ – theforestecologist Dec 1 '18 at 23:34
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    $\begingroup$ I disagree with your point about 'activation' (but not that enzymes provide a pathway of lower activation energy). Dixon & Webb in Enzymes define an enzyme as 'a protein with catalytic powers due to its power of specific activation', that is an enzyme may be though of as making a substance more reactive, and the OP uses the term in this sense. To again quote D&W: "activation is not restricted to enzymology. It is frequently used without any precise implication as to mechanism, merely to denote that the reactant molecule is made more reactive". $\endgroup$ – user1136 Dec 2 '18 at 0:00
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    $\begingroup$ I have edited my answer, as mentioned in other comments, but also replaced "error" by "problem". I suspect that that may have been poor psychology. (Must remember to go round the lab and replace all "poison" labels by "substance the non-toxicity of which cannot be guaranteed".) $\endgroup$ – David Dec 2 '18 at 11:34

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