Is there some kind of a vertical measure of appearance of a genotype $g$ throughout ancestry, i.e. a measure of how many ancestors of $g$ had genotype $g$. Like for example in saying that on average each member of a population $P$ have 60% of its ancestors having genotype $g$ over 20 prior generations.
A clarifying example, lets take some genetic trait like color, suppose we have a population $P$, and suppose we know all of the ancestry of each individual $x$ in that population up to say six generations, i.e. we know specifically the color of each mother and father of $x$, the grandmothers and grandfathers of $x$, the first great grandmothers and the first great grandfathers of $x$, up to .. the fourth great grandparents, call the set of all those as $Ancestry^6(x)$, lets denote the set of all individuals of $Ancestry^6(x)$ that are $a$ colored as $Ancestry^6_a$, let's denote the total number of members of any set $y$ by $|y|$,
Now what I'm looking at is the proportion $p^6_a(x)$ of all $a$ colored members of the 6 generations ancestry of $x$, from that ancestry.
$$p^6_a(x)=|Ancestry^6_a(x)|/|Ancestry^6(x)|=|Ancestry^6_a(x)|/(2+2^2+..+2^6)$$
Now for population $P$ we'll look for average $p^6_a(x)$: $x \in P$, symbolized as $\mu^P(p^6_a)$ which is $$\mu^P(p^6_a) = \big{(}\sum^P p^6_a(x)\big{)}/|P| $$
In general the measure is $\mu^P(p^m_a)$, where $P$ is the population, $m$ the total number of generations in the ancestry of each member of $P$, $a$ is the genotype, and $\mu$ signify average, and $p$ for proportion. So $\mu^P(p^m_a)$ is: the average proportion of genotype $a$ in ancestry of each member of $P$ up to $m$ generations.
Question: is that measure directly proportional to fitness?
The idea is that if genotype $a$ is more fit than others, then it would appear more frequently in the ancestry of each member in the population.
