Here's an interesting question I've been trying to figure out:
My annotations are in red. So far, I've figured out:
- We know 630 colonies survived when plated with ACD antibiotics...meaning they picked up the a/c/d resistance alleles, but remain wild-type for the b allele. The genotype would be "a b+ c d". Because SO MANY (630!) colonies seemed to inherit a/c/d together, and b completely separate from them, I would say b is the gene quite distant from the 3 other genes.
However, I've unsure about how to proceed and determine the probably order of the 3 others genes: a, c, and d.
Here's my hunch: B--------------------C-D-A.
Well, I looked and saw 942 (many!!!) picked up A/D together. So A/D are probably adjacent.
Then, 786 (many, but fewer) picked up C/D together. So C is further from D than A is far from D. The question becomes: is it "C---A-D" or is it "A-D---C"?
The insight comes in with 640 (still fewer) picked up A/C together. That means A is actually quite FAR from C, because more distance = more recombination events that could split them up. So between the "C---A-D" or "A-D---C" listed above, it's more likely "A-D---C".
Okay! We know B is far from the other ones, BUT is it like "B-------ADC", or is it like "ADC-------B"? Well, let's look: picked up B/C together is 51, but picked up A/B together is only 46. That means A is a little FURTHER from B than C is further from B, since 46 < 51.
- This led me to my proposed answer: that the order is "ADC---------B", or if you just flip it around, its equivalent: "B---------CDA".
How's my reasoning? This stuff can be pretty confusing; am I approaching it from the right angles? Thanks so much; really appreciate it!