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There exists a lot of literature on electroporation of Gram-positive and negative bacteria. Most of it gives an explanation that electroporation works by creating transient pores in cell membranes of bacteria for the DNA to pass through.

Both types of bacteria have a cell wall as well (differing in thickness). How does the DNA pass through the cell wall that it encounters on the way?

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The bacterial cell wall is quite porous, and is not considered a permeability barrier for most small molecules. It mainly functions as structural support and to resist turgor pressures.

The average pore size of relaxed peptidoglycans were measured to have a radius in a range of about 2.0 to 2.5 nm, regardless of thickness (i.e. Gram + and Gram - bacteria have similar pore sizes), but when stretched under turgor pressures, peptiglycan is permeable to globular proteins of 50 kDa or more, while hyperosmitic shock of bacterial cells can trigger the release of proteins up to 100 kDa in size (Vollmer et al., 2008). That equates to ~6.5 to 8.5 nm in diameter by one method of estimation.

A single strand of DNA double helix is around 2 nm in diameter, so it stands to reason that even a circularized plasmid could potentially pass through pores just a little more than 4 nm wide.

Reference:

Vollmer, W., Blanot, D., & De Pedro, M. A. (2008). Peptidoglycan structure and architecture. FEMS microbiology reviews, 32(2), 149-167.

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  • $\begingroup$ Good answer (+1) and you've done a nice job of providing a relevant supporting reference. However, in the future please include the complete reference information since links can break. One easy way to get that information is to search for the paper on Google Scholar and click on the ‟ symbol to get reference information. I've formatted your reference in way that minimizes changes to your answer, but this is another good example of how to format references. 😊 $\endgroup$
    – tyersome
    Commented Jun 26, 2020 at 1:22

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