The electron transport chain in aerobic bacteria functions by pumping H+ out of the cell to establish a concentration gradient.

So if the bacteria are placed in a buffer solution having pH equal to the cytosolic pH of the bacteria, will they still be able to establish the required concentration gradient? Will the increase in pH of cytosol(due to loss of H+) alone be enough to drive ATP synthesis even in the absence of a pH change in the medium? i.e.Will obligate aerobic bacteria die if placed in a buffer solution even in the presence of oxygen?



No. There is ample evidence that:

Most non-extremophilic bacteria grow over a broad range of external pH values, from 5.5 – 9.0, and maintain a cytoplasmic pH that lies within the narrow range of pH 7.4 – 7.8.

The explanation for this is another matter, but, before discussing that question there are two points of possible misunderstanding in the question that require a note of clarification.


  1. What the electron transport chain establishes is an electrochemical proton gradient, or proton-motive force (PMF). This consists of two components§: the hydrogen ion concentration difference, ΔpH, and the electric potential gradient, Δψ.

  2. The source referenced in the question shows hydrogen ions being pumped from the cytoplasm, across a membrane, to a space labelled “outside”, which, according to the figure legend represents hydrogen ions “pumped out of the cell”. This is incorrect. The hydrogen ions are pumped into the space between the inner and outer membranes of gram-negative bacteria, or the space between the inner membrane and cell wall of gram-positive bacteria. It cannot necessarily be assumed that this space has the same pH as the external milieu.

How is the proton motive force maintained?

A possible explanation of why a constant or, more striking, alkaline pH does not destroy the proton motive force relates to the two-component nature of the latter. Bacteria appear to be able to compensate for any decrease (or even inhibition) of either ΔpH or Δψ by a reciprocal increase in the other (Bakker and Mangerich,1961). One mechanism that illustrates how this can be achieved in certain cases is the use of an alternative terminal oxidase, cytochrome bd:

Cytochrome bd generates a PMF by transmembrane charge separation, but does so without being a proton pump.

However there is a complex set of anion co-transporters involved in cytoplasmic pH homeostasis which may influence the membrane potential. The situation is neither simple nor, as yet, completely resolved, as far as I am aware (but it’s not my field).

§ The treatment of electric potential gradient, Δψ, tends to be downplayed in biochemistry text books. This may be because the generation of a hydrogen ion gradient is easier to understand than that of a membrane potential, or because the texts deal with the latter in sections on nervous tissue. There is a quantitative treatment of the free energy changes involved in Chapter 18 of Berg et al. online.

| improve this answer | |
  • $\begingroup$ Does the electric potential gradient Δψ refer to the potential gradient due to all ions including H+ ? $\endgroup$ – trinitrotoluene Jul 12 at 4:02
  • 1
    $\begingroup$ @trinitrotoluene — Δψ is the potential gradient resulting from the membrane polarization. It has nothing to do with the ions in solution, save for any role their transport across the membrane may have had in producing this. I am not the best person to explain this further — electrophysiology is something I never studied and scares me rather. The ΔpH is easier to understand, which is one of the reasons text books focus on it. I have added a reference to Berg in my answer, where this is considered from a bioenergetics standpoint. $\endgroup$ – David Jul 12 at 11:15
  • $\begingroup$ OK thank you, I'll try looking into it myself $\endgroup$ – trinitrotoluene Jul 12 at 11:21

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.