We often represent organic matter with the following equation:
$$ (CH_2O)_x(NH_3)_y(H_3PO_4)_z \tag{0} $$
For example, the organic matter with the Redfield ratio has the form of $(CH_2O)_{106}(NH_3)_{16}(H_3PO_4)_1$.
But if we want to put inside the element Sulfur ($S$), which form below should we use?
$(CH_2O)_x(NH_3)_y(H_3PO_4)_z(H_2S)_m \tag{1}$
$(CH_2O)_x(NH_3)_y(H_3PO_4)_z(S)_m \tag{2}$
$(CH_2O)_x(NH_3)_y(H_3PO_4)_z(SO_4)_m \tag{3}$.
These different forms assume the different covalency of sulphur (-2, 0, or +6). Which form above should we take to describe the composition of organic matter with S?
I guess maybe Eq.(2) $(CH_2O)_x(NH_3)_y(H_3PO_4)_z(S)_m$? Because in this way, sulfur has the covalency of zero, which is the same as carbon (0).
I asked this question because I found many papers use the Eq.0 to build the mineralization of organic matter (e.g., O2 oxidation, [R1] in Table 2 here. See Fig.1 below). The amount of O2 depends on the assumption that carbon in OM has the covelency of zero (then, 1 mole of C corresponds to 1 mole of O2).
Since I didn't find a paper that put S into the OM compositon to balance the similar equation like [R1] in Fig.1, I am curious about which covalency value is "more common" for such an equation (because Sulfur's covalency can affect the amount of O2 needed).