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2 votes

How does $\ce{H2CO3}$ form in the blood with a ratio of 1:20 with $\ce{HCO3-}$ if there are not enough $\ce{H+}$ ions

Bicarbonate and its conjugate acid buffer the blood due to their intrinsic behavior (pKa/pKb) of donating $H^{+}$ if there is too few (high pH) or taking up $H^{+}$ if there is too much (low pH). You ...
KaPy3141's user avatar
  • 1,597
1 vote

How does $\ce{H2CO3}$ form in the blood with a ratio of 1:20 with $\ce{HCO3-}$ if there are not enough $\ce{H+}$ ions

It has to do with the buffering activity of Hb and $\ce{HCO3-}$ leakage. $\ce{H2CO3}$ dissosiates inside the RBCs and the resulting protons, $\ce{H+},$ bind to Hb, decreasing proton pressure caused by ...
user7777777's user avatar

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