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-1

Tyersome is correct. Just adding a bit of explanation. This constant (let's call it $K_M$ to avoid any confusion) is the ligand concentration at half saturation. $K_d$ is the dissociation constant as you mentioned. when $Y=0.5$ $\begin{align} K_d &= (p\ce{O_2})^n\\[0.5em] p\ce{O_2} &= \sqrt[n]{K_d} = K_M \end{align}$


3

In your second step $(K_d)^n$ should be $(K_A)^n$. Where: $K_d$ is the apparent dissociation constant and $K_{A}$ is the ligand concentration that results in half occupation See for example the relevant wikipedia article.


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