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May 8, 2015 at 22:34 history edited falsum CC BY-SA 3.0
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May 8, 2015 at 19:04 history edited falsum CC BY-SA 3.0
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May 8, 2015 at 18:59 comment added falsum My impression is that, in the example above, your equation yields $w_c = w_0 + x (b-c) + (1-x)(-c) = w_0 + xb - c$. The chance of a cooperator meeting another cooperator will be $(k-1)/(2-1)=(k-1)$, which gives the equation I wrote. Am I missing something?
May 8, 2015 at 18:41 comment added Remi.b $b$ and $c$ doesn't have the standard definition as given by Hamilton. The fitness of an individual who cooperates is usually computed as $w_c = w_0 + x PO_{cc} + (1-x)PO_{cd}$, where $PO_{cd}$ is the payoff of an individual who cooperates when meeting an individual who defects and $x$ is the frequency of cooperators in the population.
May 8, 2015 at 17:57 history edited falsum CC BY-SA 3.0
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May 8, 2015 at 17:51 history answered falsum CC BY-SA 3.0