Under Hardy-Weinberg conditions, the frequency of the genotype abcd (in this particular order) is simply $F_a \cdot F_b \cdot F_c \cdot F_d$.

The probability of abcd in any particular order is simply $24 * F_a \cdot F_b \cdot F_c \cdot F_d$. 24 (=432*1) is the number of ways you can get this particular order.

You might want to have a look at the post Solving Hardy Weinberg problems

Under Hardy-Weinberg conditions, the frequency of the genotype abcd (in this particular order) is simply $F_a \cdot F_b \cdot F_c \cdot F_d = 0.24\%$.

If we don't consider the order, then we must ultiply the previous probability by 24. There are indeed 24 (=432*1) ways you can get this particular combination. The probability of abcd in any particular order is therefore $24 \cdot F_a \cdot F_b \cdot F_c \cdot F_d = 5.76\%$.

You might want to have a look at the post Solving Hardy Weinberg problems

Under Hardy-Weinberg conditions, the frequency of the genotype abcd is simply $F_a \cdot F_b \cdot F_c \cdot F_d$.

For more information, please see the post Solving Hardy Weinberg problems

Under Hardy-Weinberg conditions, the frequency of the genotype abcd (in this particular order) is simply $F_a \cdot F_b \cdot F_c \cdot F_d$.

The probability of abcd in any particular order is simply $24 * F_a \cdot F_b \cdot F_c \cdot F_d$. 24 (=432*1) is the number of ways you can get this particular order.

You might want to have a look at the post Solving Hardy Weinberg problems