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corrected the EcoRI recognition sequence
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acvill
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I have seen that the formula to calculate the number of times a given sequence of nucleotides occur in a target genome is derived from that to calculate the expected frequency of restriction sites:

a = (g/2)^G+C × ((1-g)/2)^A+T,

where:

a = probability
g = G+C content of the target genome
C+G = number of G and C in the stretch
A+T = number of A and T in the stretch.

An example was given for the mitochondrial genome and the restriction site for EcoRI (GATTCGAATTC). I calculated, based on the example:

a = (0.44/2)^2 × (1-0.44)^4 = 0.0005

given that the length m of the mitochndrial genome is 16 000 bp, the number of occurrences is:

n = am = 0.0005 × 16 000 = 4.92 (against 4.80 reported in the paper).

I then tried to calculate the occurrence of a primer based targeting E. coli: GTGTCCATTTATACGGACATCCATG. The GC content of E. coli is 50.8%, thus:

a = (0.58/2)^11 × (0.42)^14 = 1.22×10^-6 * 3.24×10^-10 = 3.95×10^-16

and the number of occurrences is:

n = 3.95×10^-16 × 16*10^6 = 6.32×10-9

Looks to me, that the primer should not occur at all in the E. coli genome.

Are the formula and its application correct? Also, I don't like the fact that one needs to know the CG content beforehand (although, one can assume 50% content) and an exponent at the 11th power; is there an alternative formula?

Thank you.

I have seen that the formula to calculate the number of times a given sequence of nucleotides occur in a target genome is derived from that to calculate the expected frequency of restriction sites:

a = (g/2)^G+C × ((1-g)/2)^A+T,

where:

a = probability
g = G+C content of the target genome
C+G = number of G and C in the stretch
A+T = number of A and T in the stretch.

An example was given for the mitochondrial genome and the restriction site for EcoRI (GATTC). I calculated, based on the example:

a = (0.44/2)^2 × (1-0.44)^4 = 0.0005

given that the length m of the mitochndrial genome is 16 000 bp, the number of occurrences is:

n = am = 0.0005 × 16 000 = 4.92 (against 4.80 reported in the paper).

I then tried to calculate the occurrence of a primer based targeting E. coli: GTGTCCATTTATACGGACATCCATG. The GC content of E. coli is 50.8%, thus:

a = (0.58/2)^11 × (0.42)^14 = 1.22×10^-6 * 3.24×10^-10 = 3.95×10^-16

and the number of occurrences is:

n = 3.95×10^-16 × 16*10^6 = 6.32×10-9

Looks to me, that the primer should not occur at all in the E. coli genome.

Are the formula and its application correct? Also, I don't like the fact that one needs to know the CG content beforehand (although, one can assume 50% content) and an exponent at the 11th power; is there an alternative formula?

Thank you.

I have seen that the formula to calculate the number of times a given sequence of nucleotides occur in a target genome is derived from that to calculate the expected frequency of restriction sites:

a = (g/2)^G+C × ((1-g)/2)^A+T,

where:

a = probability
g = G+C content of the target genome
C+G = number of G and C in the stretch
A+T = number of A and T in the stretch.

An example was given for the mitochondrial genome and the restriction site for EcoRI (GAATTC). I calculated, based on the example:

a = (0.44/2)^2 × (1-0.44)^4 = 0.0005

given that the length m of the mitochndrial genome is 16 000 bp, the number of occurrences is:

n = am = 0.0005 × 16 000 = 4.92 (against 4.80 reported in the paper).

I then tried to calculate the occurrence of a primer based targeting E. coli: GTGTCCATTTATACGGACATCCATG. The GC content of E. coli is 50.8%, thus:

a = (0.58/2)^11 × (0.42)^14 = 1.22×10^-6 * 3.24×10^-10 = 3.95×10^-16

and the number of occurrences is:

n = 3.95×10^-16 × 16*10^6 = 6.32×10-9

Looks to me, that the primer should not occur at all in the E. coli genome.

Are the formula and its application correct? Also, I don't like the fact that one needs to know the CG content beforehand (although, one can assume 50% content) and an exponent at the 11th power; is there an alternative formula?

Thank you.

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Gigiux
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How to calculate the occurrence of a stretch of nucleotides in a genome?

I have seen that the formula to calculate the number of times a given sequence of nucleotides occur in a target genome is derived from that to calculate the expected frequency of restriction sites:

a = (g/2)^G+C × ((1-g)/2)^A+T,

where:

a = probability
g = G+C content of the target genome
C+G = number of G and C in the stretch
A+T = number of A and T in the stretch.

An example was given for the mitochondrial genome and the restriction site for EcoRI (GATTC). I calculated, based on the example:

a = (0.44/2)^2 × (1-0.44)^4 = 0.0005

given that the length m of the mitochndrial genome is 16 000 bp, the number of occurrences is:

n = am = 0.0005 × 16 000 = 4.92 (against 4.80 reported in the paper).

I then tried to calculate the occurrence of a primer based targeting E. coli: GTGTCCATTTATACGGACATCCATG. The GC content of E. coli is 50.8%, thus:

a = (0.58/2)^11 × (0.42)^14 = 1.22×10^-6 * 3.24×10^-10 = 3.95×10^-16

and the number of occurrences is:

n = 3.95×10^-16 × 16*10^6 = 6.32×10-9

Looks to me, that the primer should not occur at all in the E. coli genome.

Are the formula and its application correct? Also, I don't like the fact that one needs to know the CG content beforehand (although, one can assume 50% content) and an exponent at the 11th power; is there an alternative formula?

Thank you.