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Reverted to original in view of the book author's deliberate use of the undefined Pi
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David
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conversion of G3P to 1,3-bisphosphoglycerateconversion of G3P to 1,3-bisphosphoglycerate (from Fundamentals of Biochemistry by Voet, 5th ed. — modified, replacing Pi by orthophosphate)

In this step of glycolysis, I'm not seeing where the $\ce{H+}$ ion on the product side is coming from. It seems to me that the G3P's aldehydic H is replaced by phosphate, and that H is given to $\ce{NAD+}$ to make NADH. So where is the extra $\ce{H+}$ coming from?

conversion of G3P to 1,3-bisphosphoglycerate (from Fundamentals of Biochemistry by Voet, 5th ed. — modified, replacing Pi by orthophosphate)

In this step of glycolysis, I'm not seeing where the $\ce{H+}$ ion on the product side is coming from. It seems to me that the G3P's aldehydic H is replaced by phosphate, and that H is given to $\ce{NAD+}$ to make NADH. So where is the extra $\ce{H+}$ coming from?

conversion of G3P to 1,3-bisphosphoglycerate (from Fundamentals of Biochemistry by Voet, 5th ed.)

In this step of glycolysis, I'm not seeing where the $\ce{H+}$ ion on the product side is coming from. It seems to me that the G3P's aldehydic H is replaced by phosphate, and that H is given to $\ce{NAD+}$ to make NADH. So where is the extra $\ce{H+}$ coming from?

I have replaced Pi by the formula for orthophosphate
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David
  • 26.6k
  • 8
  • 53
  • 95

conversion of G3P to 1,3-bisphosphoglycerateconversion of G3P to 1,3-bisphosphoglycerate (from Fundamentals of Biochemistry by Voet, 5th ed. — modified, replacing Pi by orthophosphate)

In this step of glycolysis, I'm not seeing where the $\ce{H+}$ ion on the product side is coming from. It seems to me that the G3P's aldehydic H is replaced by phosphate, and that H is given to $\ce{NAD+}$ to make NADH. So where is the extra $\ce{H+}$ coming from?

conversion of G3P to 1,3-bisphosphoglycerate (from Fundamentals of Biochemistry by Voet, 5th ed)

In this step of glycolysis, I'm not seeing where the $\ce{H+}$ ion on the product side is coming from. It seems to me that the G3P's aldehydic H is replaced by phosphate, and that H is given to $\ce{NAD+}$ to make NADH. So where is the extra $\ce{H+}$ coming from?

conversion of G3P to 1,3-bisphosphoglycerate (from Fundamentals of Biochemistry by Voet, 5th ed. — modified, replacing Pi by orthophosphate)

In this step of glycolysis, I'm not seeing where the $\ce{H+}$ ion on the product side is coming from. It seems to me that the G3P's aldehydic H is replaced by phosphate, and that H is given to $\ce{NAD+}$ to make NADH. So where is the extra $\ce{H+}$ coming from?

Tweeted twitter.com/StackBiology/status/799880348184248321
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Where is the H+ ion in this step of glycolysis coming from?

conversion of G3P to 1,3-bisphosphoglycerate (from Fundamentals of Biochemistry by Voet, 5th ed)

In this step of glycolysis, I'm not seeing where the $\ce{H+}$ ion on the product side is coming from. It seems to me that the G3P's aldehydic H is replaced by phosphate, and that H is given to $\ce{NAD+}$ to make NADH. So where is the extra $\ce{H+}$ coming from?