I have a few issues with this question.
An enzyme assay is performed and the kinetic data graphed. The y-intercept of a Lineweaver-Burk plot is 0.6 min/ΔA. The substrate being assayed has a molar absorbance coefficient (ε) of 4500 L/mol.cm. What is the V max of the enzyme in mmol/L.min?
Vmax = 1 / 0.6min/ΔA = 1.66ΔA/min (the units switch back I believe?)
And then 1.66ΔA/min / 4.5L/mmol.cm to get 0.37 mmol/L.min?