2
$\begingroup$

Why should you use an annealing temperature about 5°C below the Tm of your primers?

According to my current research, I think it has something to do with the other reactents in the PCR, but I am not sure.

$\endgroup$
3
  • $\begingroup$ What's your problem with the answer? Some criticism would help to make it better... $\endgroup$
    – Chris
    Commented Oct 17, 2017 at 19:55
  • $\begingroup$ My understanding of this concept was recently corrected by a prof, and your explanation did not seem to get to the point. I will add the answer the prof gave me. $\endgroup$ Commented Oct 19, 2017 at 18:09
  • $\begingroup$ I haven't seen this yet - do you have a literature source for it? $\endgroup$
    – Chris
    Commented Oct 19, 2017 at 18:36

2 Answers 2

2
$\begingroup$

You want to have primers which bind under the conditions of the reaction only to your sequence of interest. If you go too far off the optimal annealing temperature (5°C below the Tm is indeed a relatively good choice in my experience), your will affect the PCR efficency and thus the yield of your reaction.

An annealing temperature, which is much too low allows annealing of your primers to other sites than your intended target with partial annealing or internal base mismatches. This leads to unspecific amplification and lower yields.

If the annealing temperature is too high no primer binding can happen and you will get not PCR product. Alternatively, partial binding can also lead to misprimed products, although this is much less likely than getting no product at all.

$\endgroup$
1
$\begingroup$

The annealing temperature of a primer is defined as the temperature in which 50% of the nucleotides of the primer are bound to the DNA. 50% annealing proportion will not yield an optimal PCT product. Thus, by lowering the temperature by around 5oC, the proportion of bound primer changes to more then 50% (perhaps around 70 - 80%) thus getting a more precise yield.

This is why we subtract 5oC from the theoretical annealing temperature.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .